X^2+12x-925=0

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Solution for X^2+12x-925=0 equation: 



X^2+12X-925=0

a = 1; b = 12; c = -925;
Δ = b2-4ac
Δ = 122-4·1·(-925)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-62}{2*1}=\frac{-74}{2}
=-37
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+62}{2*1}=\frac{50}{2}
=25
$

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